HurwitzLerchPhi

HurwitzLerchPhi[z,s,a] gives the Hurwitz–Lerch transcendent Φ(z,s,a).

Examples

Evaluate the Hurwitz-Lerch transcendent:

HurwitzLerchPhi[1/2, 2, 1]
(* Pi^2/12 - Log[2]^2/2 *)

Numerical evaluation:

N[HurwitzLerchPhi[0.5, 2, 3]]
(* 0.138629 *)

Please visit the official Wolfram Language Reference for more details.